Gabyyyyy Gabyyyyy

04-03-2016
Mathematics

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What are the solutions to 4x^2 +25=0

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garydesir1 garydesir1

04-03-2016

[tex] \sqrt{x} \sqrt{x} -25/4 no real solution [/tex]Subtract 25 from both sides

4x^2+25-25 = 0-25

4x^2= -25

Divide both sides by 4

4x^2/4=-25/4

x^2= -25/4

Take square root

x+- square root -25/4

No solution .

I hope that's help.

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