Answer:
hello : b = -24 and a =13
Step-by-step explanation:
let : f(x) = x3+10x2+ax+b
( x - 1 ) and ( x+3) are the factors
so : 1 and - 3 are the zeros of x3+10x2+ax+b
f(1) = 0 and f(-3) = 0
f(1) = 0 : 1^3 + 10 (1)² + a(1) + b =0
a + b + 11 = 0 ......(*)
f(-3) = 0 : (-3)^3 +10(-3)² +a(-3) +b = 0....but (-3)^3 +10(-3)² = -27+90 = 63
- 3a + b + 63 = 0 ......(**)
(*) - (**) ; a + b + 11 +3a -b - 63 =0
4a = 52
a = 13
subsct(*) in : 13 + b +11 = 0
b = - 24
second solution: look here
