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15-03-2019
Physics

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Two positive charges are seperated by 12 cm. The force thatq1 exerts on q2 is 4×10 ^8N. what is this force if the distance between the two charges is reduced to 9cm?

Two positive charges are seperated by 12 cm The force thatq1 exerts on q2 is 410 8N what is this force if the distance between the two charges is reduced to 9cm class=

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15-03-2019

The new force is 7.11 x 10^8 N.

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