Answer:
[tex]-0.4(3x-2)+\frac{2x+4}{3}=0\ \textrm{for}\ x=4[/tex]
Step-by-step explanation:
Given:
The expression to evaluate is given as:
[tex]-0.4(3x-2)+\frac{2x+4}{3}[/tex]
The value of 'x' is 4.
Plug in 4 for 'x' in the above expression and simplify. This gives,
[tex]=-0.4(3(4)-2)+\frac{2(4)+4}{3}\\=-0.4(12-2)+\frac{8+4}{3}\\=-0.4(10)+\frac{12}{3}\\=-4+4\\=0[/tex]
Therefore, the value of the given expression for 'x' equal to 4 is 0.
