jping6772
jping6772 jping6772
  • 15-04-2020
  • Mathematics
contestada

h(1)=−2
h(2)=1
h(n)=h(n−2)+h(n−1)
what is h(3)??? ​

Respuesta :

xxNMNxx
xxNMNxx xxNMNxx
  • 15-04-2020

Answer:

h(3) = -1

Step-by-step explanation:

h(n) = h(n-2) + h(n-1)

h(3) = -2 + 1

h (3) = -1

Answer Link
jiaojason2020
jiaojason2020 jiaojason2020
  • 10-03-2021

Answer:

-1

Step-by-step explanation:

Answer Link

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