Answer:
[tex]m_{BeCl_2}=18.6gBeCl_2[/tex]
Explanation:
Hello,
In this case, we first relate the given formula units of beryllium chloride as molecules with moles by using the Avogadro's number:
[tex]n_{BeCl_2}=1.4x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules}=0.23molBeCl_2[/tex]
Now, we use its molar mass (80g/mol) to compute the required mass:
[tex]m_{BeCl_2}=0.23molBeCl_2 *\frac{80gBeCl_2}{1molBeCl_2} \\\\m_{BeCl_2}=18.6gBeCl_2[/tex]
Best regards.
