Respuesta :

sebassandin

Answer:

[tex]\Delta _mS=7.63\frac{J}{mol*K}[/tex]

Explanation:

Hello,

In this case the entropy of fusion is associated with the enthalpy and the temperature when a solid goes liquid and takes the form:

[tex]\Delta _mS=\frac{\Delta _mH}{T}[/tex]

Whereas the temperature must be in absolute Kelvins:

[tex]\Delta _mS=\frac{13.8kJ/mol}{(1535+273.15)K}*\frac{1000J}{1kJ} \\\\\Delta _mS=7.63\frac{J}{mol*K}[/tex]

Best regards.

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