Answer:
The correct answer is 0.89 mol.
Explanation:
At STP (Standard Temperature and Pressure) conditions, 1 mol of an ideal gas occupies a volume of 22.4 L. If we assume STP conditions, we can consider a convertion factor of 1 mol/22.4 L to convert the volume of NO₂ from liters to moles:
20,00 L x 1 mol/22.4 L = 0.89 mol
So, at STP, we would have 0.89 mol of NO₂
