abigailbarnes8242 abigailbarnes8242
  • 04-02-2021
  • Mathematics
contestada

Solve the equation for x:
sin^2 x – 2 cos x - 2 = 0
for the restriction 0 < x < 2pi

Solve the equation for x sin2 x 2 cos x 2 0 for the restriction 0 lt x lt 2pi class=

Respuesta :

Аноним Аноним
  • 04-02-2021

Answer: x = pi

sin²x - 2cos x - 2 = 0

⇔ 1 - cos²x - 2cos x - 2 = 0

⇔ cos²x + 2cos x + 1 = 0

⇔ (cos x + 1)² = 0

⇒ cos x + 1 = 0

⇔ cos x = -1

⇒ x = pi + k2pi

because 0 ≤ x < 2pi

=> x = pi

Step-by-step explanation:

Answer Link

Otras preguntas

If an airplane in a 1 in : 2 ft scale drawing is 6 inches long, how long is the actual airplane? 12 ft 24 ft 8 ft 3 ft.
pick the odd one outa) tenb) eight c) four d) seven​
what is the height of h of the triangle?
what is the percent by volume of a hydrogen peroxideA. 0.5%B. 1.7%C. 3.6%D. 97.3%​
The circumference of a circle is 20pi m. find its diameter,in meters
What is the proper food to eat before, during, and after the exercise/physical activities? Why?​
is this statement true or false? In most states, the law provides that all employers must give time off to employees to vote true alise
5. Identify the vertex of the parabola. A. (6, 3) B. (3, 0) C. (4, -1) D. (5, 0)
There is sandwich meat in the refrigerator. There is 2 and 3/4 pounds of roast beef, 1 and 7/8 pounds of turkey, and 2 1/16 pounds of salami. If you must put 1/
The Sayyid dynasty followed the (a) Slave dynasty (b) Khilji dynasty (c) Tughlaq dynasty (d) Lodhi dynasty​