praolg
praolg praolg
  • 04-01-2017
  • Mathematics
contestada

rozwiąż równanie kwadratowe: 3/4 y^2 +9=y/2+(y-3)^2

Respuesta :

LammettHash
LammettHash LammettHash
  • 04-01-2017
Najpierw rozszerz po prawej strony równania.

[tex]\dfrac34y^2+9=\dfrac y2+(y-3)^2\implies\dfrac34y^2+9=\dfrac y2+y^2-6y+9[/tex]

Przenieść wszystko na jedną stronę i uproszcz.

[tex]\dfrac{y^2}4-\dfrac{11y}2=0[/tex]

Rozkładaj lewą stronę na czynniki.

[tex]\dfrac14y(y-22)=0[/tex]

Są dwa rozwiązania,

[tex]y=0\text{ i }y=22[/tex]
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