tli8322 tli8322
  • 04-08-2022
  • Mathematics
contestada

How do I solve “1+2+3+4+5+…100=“
A. 1010
B. 5050
C. 5000
D. 1000

Respuesta :

jetsungyembo
jetsungyembo jetsungyembo
  • 04-08-2022

Answer:

5050

Step-by-step explanation:

we know that 100/2 is 50 and 50 x 100 is 5000

so now another 50 is remaining but we can't multiply but add so

1+2+3+4+5...100 = in simple form= 50x100+50=5050//

Answer Link

Otras preguntas

What is the given equation in logarithmic form of 7^4=2,401?
How do you solve p+9 <7 AND graph it???
Did Maya Angelou's uncle kill the mom's boyfriend after finding out he raped Maya or beat him to death?
Determine the type and number of solutions of 7x^2+3x+8=0
what's the square root of 135
solve for x₁ and x₂6x₁+3x₂=606x₁-2x₂=80
What Is a Zionist? Please help me :)
what is an undefined nuclear region containing only nucleic acid
Find the remainder when 2x^4-6x^3+2x^2-x+2 is divided by x+2
A microscope is set so it makes an object appear 4 x 10`2 times larger than its actual size. A virus has a diameter of of 2 x 10`-7 meter. how large will the di