RusselD248291 RusselD248291
  • 03-11-2022
  • Mathematics
contestada

Suppose that a variable has a binomial distribution with n=18 and p=0.48 what is the expected value of the variable?

Suppose that a variable has a binomial distribution with n18 and p048 what is the expected value of the variable class=

Respuesta :

NishaanS197970 NishaanS197970
  • 03-11-2022

Answer:

8.64

Explanation:

The expected value for a binomial distribution is equal to

E = np

Where n is the number of trials and p is the probability of success. In this case, n = 18 and p = 0.48. Then, the expected value is

E = (18)(0.48)

E = 8.64

Therefore, the answer is 8.64

Answer Link

Otras preguntas

whats 25/7 as a mixed number?
12/2 as a whole number or mixed number
i need a paragraph on work experience like where i went ,what i did,what my boss was like and what i did during the work experience ? can anyone help?!
how do you use distributive property to find the answer of 75 divided by 3
factor completely if the polynomial is not factorable write prime also state the methods used to factor the polynomial. 1. x^2-12x+36 2. r^3-81r 3. 35x^3y
50/7 as a mixed number
how do you compare 1/5 and 0.201
What is 1/3 of 9 if u know please tell me thanks
How to put this an equation (an athlete trains for 115min each day for as many days as possible. Write an equation that relates the number of days d that the at
what is 62.6 rounded to the nearest tenth