casperchief8601 casperchief8601
  • 04-05-2018
  • Chemistry
contestada

What is the celsius temperature of 100.0 g of chlorine gas in a 55.0-l container at 800 mm hg?

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PBCHEM
PBCHEM PBCHEM
  • 12-05-2018
Given, pressure = P = 800 mm Hg = 1.066 X 10^5 Pa
Volume = V = 55 l = 0.055 m^3
number of moles of Cl2 gas = n = [tex] \frac{weight}{\text{molecular weight}} [/tex] = [tex] \frac{100}{71} [/tex] = 1.408

Now, based on ideal gas equation, we have
PV=nRT
∴ T = PV/RT
where R = universal gas constant = 8.314 J /mol K
∴ T = [tex] \frac{1.066X 10^5X0.055}{1.408X8.314} [/tex] = 500.8 K

Now, we know that [tex] 0^{0}C = 273.15 K [/tex]
∴ 500.8 K = [tex] 227.65^{0}C [/tex]
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